You are here
A truck driver driving at the speed of 54 km h⁻¹ notices a road sign with a speed limit of 40 km h⁻¹ (Fig. 4.29) for trucks. He slows down to 36 km h⁻¹ in 36 s. What was the distance travelled by him during this time? Assume the acceleration to be constant while slowing down.
Show Answer
u = 54 km h -1 = 15 m s -1 , v = 36 km h -1 = 10 m s -1 , t = 36 s .
Distance = average velocity × time = 15 + 10 2 × 36 = 12.5 × 36 = 450 m .
| Quantity | Value |
|---|---|
| Initial velocity u | 15 m/s |
| Final velocity v | 10 m/s |
| Time t | 36 s |
| Distance travelled | 450 m |
