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On entering a state highway, a car continues to move with a constant velocity of 6 m s⁻¹ for 2 minutes and then accelerates with a constant acceleration 1 m s⁻² for 6 seconds. Find the displacement of the car on the state highway in the 2 min 6 s time interval by drawing a velocity-time graph for its motion.
Show Answer
Phase 1 (constant): s 1 = 6 × 120 = 720 m .
Phase 2 (accelerating): s 2 = ut + 1 2 at 2 = 6(6) + 1 2 (1)(6 2 ) = 36 + 18 = 54 m .
Total displacement = 720 + 54 = 774 m (the total area under the velocity-time graph).
| Phase | Distance |
|---|---|
| Constant velocity (2 min) | 720 m |
| Accelerating (6 s) | 54 m |
| Total displacement | 774 m |
