Using the formula tn = a + (n – 1) × d, find the nth term of the - Visualising an AP

part 2 - Exercise Question 2 (Page 182) - Visualising an AP - Chapter 8 - Predicting What Comes Next: Exploring Sequences & Progress - Class 9
part 3 - Exercise Question 2 (Page 182) - Visualising an AP - Chapter 8 - Predicting What Comes Next: Exploring Sequences & Progress - Class 9 part 4 - Exercise Question 2 (Page 182) - Visualising an AP - Chapter 8 - Predicting What Comes Next: Exploring Sequences & Progress - Class 9

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Exercise Question 2 (Page 182) (i) Using the formula 𝑑_𝑛=π‘Ž+(π‘›βˆ’1)×𝑑, find the nth term of the following arithmetic progressions. (i) 1/2, 5/2, 9/2, 13/2,… Here, First term = a = 𝟏/𝟐 Common difference = d = 5/2βˆ’1/2 = (5 βˆ’ 1)/2 = 4/2 = 2 Now, nth term = 𝑑_𝑛 = a + (n – 1) Γ— d Putting values = 𝟏/𝟐+(π’βˆ’πŸ) Γ— 𝟐 = 1/2+2π‘›βˆ’2 = 2𝑛+(1βˆ’ 2 Γ— 2)/2 = πŸπ’βˆ’πŸ‘/𝟐 = a + (n – 1) Γ— d Putting values = 𝟏/𝟐+(π’βˆ’πŸ) Γ— 𝟐 = 1/2+2π‘›βˆ’2 = 2𝑛+(1βˆ’ 2 Γ— 2)/2 = πŸπ’βˆ’πŸ‘/𝟐 Exercise Question 2 (Page 182) (ii) Exercise Using the formula 𝑑_𝑛=π‘Ž+(π‘›βˆ’1)×𝑑, find the 𝑛^"th " term of the following arithmetic progressions. (ii) 1.5, 3.5, 5.5, 7.5,… Here, First term = a = 1.5 Common difference = d = 3.5 – 1.5 = 2 Now, nth term = 𝑑_𝑛 = a + (n – 1) Γ— d Putting values = 1.5 + (n – 1) Γ— 2 = 1.5 + 2n – 2 = 2n – 0.5 = 1.5 + (n – 1) Γ— 2 = 1.5 + 2n – 2 = 2n – 0.5

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