Predicting What Comes Next: Exploring Sequences & Progress - Class 9

Master Predicting What Comes Next: Exploring Sequences & Progress - Class 9 with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.

NCERT Solutions

Predicting What Comes Next: Exploring Sequences & Progress - Class 9 – NCERT Solutions

Each question below opens its complete step-by-step Teachoo solution.

Exercise Set 8.1

6 questions

Ex 8.1, 1

(i) Find the first five terms of the sequence in which the nth term is given by
(i) 𝑡_𝑛=3𝑛−4
We need to find first five terms
i.e. 𝒕_𝟏, 𝒕_𝟐, 𝒕_𝟑, 𝒕_𝟒, 𝒕_𝟓

View solution

Ex 8.1, 2

Find the 10th and 15th terms of the sequence 𝑡_𝑛=5𝑛−3 for 𝑛≥1.
Given 𝑡_𝑛=5𝑛−3

View solution

Ex 8.1, 3

Determine whether 97 and 172 are terms of the sequence 𝑡_𝑛=5𝑛−3 "for " 𝑛≥1"."
To check whether 97 and 172 are terms of sequence
We put 𝑡_𝑛 = 97 and find n

View solution

Ex 8.1, 4

Which term of the sequence 𝑡_𝑛=5𝑛−3 for 𝑛≥1 is 607?
To check which term is 607 of the sequence
We put 𝑡_𝑛 = 607 and find n

View solution

Ex 8.1, 5

A sequence is given by the recursive rule 𝑡_1=−5,𝑡_(𝑛+1)=𝑡_𝑛+3 for 𝑛≥1. Find the first five terms of the sequence. Is 52 a term of this sequence? If so, which term is it?
First, let’s find first five terms
i.e. 𝒕_𝟏, 𝒕_𝟐, 𝒕_𝟑, 𝒕_𝟒, 𝒕_𝟓

View solution

Ex 8.1, 6

Let T_1=1,〖" " T〗_2=2,〖" " T〗_3=4, and T_n=T_(n−1)+T_(n−2)+T_(n−3) for 𝑛≥4. Find T_4,〖" " T〗_5,〖" " T〗_6,〖" " T〗_7, and T_8.
Given
T_1=1
T_2=2
T_3=4

View solution

Exercise Set 8.2

7 questions

Ex 8.2, 1

Find the 10th and 26th terms of the AP 3, 8, 13, 18,….
Given AP
3, 8, 13,18, …

View solution

Ex 8.2, 2

Which term of the AP 21, 18, 15,… is -81 ? Also, is 0 a term of this AP? Give reasons for your answer.
Given AP
21, 18, 15, …….

View solution

Ex 8.2, 3

Find the nth term of the AP 11, 8, 5, 2, …. Write the recursive rule for this AP.
Given AP
11, 8, 5, 2, ….

View solution

Ex 8.2, 4

An A.P. consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term.
(Hint If '𝑎' is the first term and '𝑑' the common difference, then we arrive at the equations 𝑎+2𝑑=12 and 𝑎+49𝑑=106. Solve this pair of linear equations for '𝑎' and '𝑑'.)
For an AP, we know that
an = a + (n – 1) d

View solution

Ex 8.2, 5

How many 2 -digit numbers are divisible by 3? What is the sum of all these 2-digit numbers?
Numbers divisible by 3 are
3, 6, 9, 12, ….

View solution

Ex 8.2, 6

Harish started work at an annual salary of ₹ 5,00,000 and received an increment of ₹ 20,000 each year. After how many years did his income reach ₹ 7,00,000?
Now,
Salary in 1st year = ₹ 5,00,000
Salary in 2nd year = 5,00,000 + 20,000 = ₹ 5,20,000
Salary in 3rd year = 5,20,000 + 20,000 = ₹ 5,40,000

View solution

Ex 8.2, 7

A child arranges marbles in rows so that the first row has 1 marble, the second has 2 marbles, the third has 3, and so on up to 25 rows. How many marbles does the child use in all?
Our sequence of marbles are
1, 2, 3, 4, 5, …. 25 rows

View solution

Exercise Set 8.3

7 questions

Ex 8.3, 1

Find the 12th term of a GP with common ratio 2 , whose 8th term is 192.
We know that for a GP
nth term = 𝒂_𝒏=〖𝒂𝒓〗^(𝒏−𝟏)

View solution

Ex 8.3, 2

Find the 10th and nth terms of the GP: 5, 25, 125,….
Given GP
5, 25, 125, ….

View solution

Ex 8.3, 3

A sequence is given by the recursive rule 𝑡_1=2,𝑡_(𝑛+1)=3𝑡_𝑛−2 for 𝑛≥1. Which term of the sequence is 730?
Let’s find the sequence from the rule
First term = 𝒕_𝟏=𝟐

View solution

Ex 8.3, 4

Which term of the GP: 2, 6, 18,… is 4374 ? Write the explicit formula as well as the recursive formula for the nth term.
Given G.P.,
2, 6, 18, ...upto n terms

View solution

Ex 8.3, 5

(i) A ball is dropped from a height of 80 metres. After hitting the ground, it bounces back to 60% of the height from which it fell. It continues bouncing in this way-each time rising to 60% of the previous height. (i) What height does the ball reach after the 5th bounce?
The ball bouncing looks like
Given that
Initial drop height: 80 metres
Bounce ratio (r): 60% or 0.6

View solution

Ex 8.3, 6

Which term of the sequence 2, 2√2,4,… is 128?
Given GP
2, 2√2,4,…

View solution

Ex 8.3, 7

Fig. 8.12 shows Stages 0 to 3 of the Sierpiński square carpet. Stage 0 of this fractal is a square sheet of paper. To construct Stage 1, each side of the square is trisected and the points of trisection of opposite sides are joined to obtain nine smaller squares. The centre square is then removed and the 8 smaller squares are retained, leaving a square hole in the centre. The same process is repeated on the eight smaller shaded squares to obtain Stage 2 and so on.
Ex 8.3, 7 (i) How many red squares are there in Stages 0 to 3?
At each stage, every existing square is split into 9 smaller squares, and the middle one is removed. This means we keep 8 squares for every 1 square we had previously.
Stage 0: 1
Stage 1: 8
Stage 2: 8 × 8 = 64
Stage 3: 64 × 8 = 512
Ex 8.3, 7 (ii) Can you predict the number of red squares in Stages 4 and 5?
We just continue multiplying by our common ratio of 8.
Stage 4: 512 × 8 = 4,096 squares
Stage 5: 4096 × 8 = 32,768 squares
Ex 8.3, 7 (iii) Can you find a rule for the number of red squares at the 𝑛^"th " stage? Write the explicit formula as well as the recursive formula for the number of red squares at any stage.
Explicit Formula
Because we are multiplying by 8 at each stage (starting at Stage 0), the stage number is the exponent. The explicit rule is
𝒕_𝒏=𝟖^𝒏

View solution

End-of-Chapter Exercises

15 questions

Question 1

Find the 31st term of an A.P. whose 11th term is 38 and the 16th term is 73
We know that
an = a + (n – 1) d
Given 11th term is 38
a11 = a + (11 – 1) d
38 = a + (11 – 1)d
38 = a + 10 d
38 – 10 d = a
a = 38 – 10d
Given 16th term is 73
a16 = a + (16 – 1)d
a16 = a + 15d
73 = a + 15d
73 – 15d = a
a = 73 – 15d
From (1) & (2)
38 – 10d = 73 – 15d
38 – 73 = –15d – 10d
–35 = –5d
(−35)/(−5) = d
7 = d
d = 7

View solution

Question 2

Determine the A.P. whose third term is 16 and the 7th term exceeds the 5th term by 12
We know that
an = a + (n – 1) d

View solution

Question 3

How many three-digit numbers are divisible by 7?
(Hint: All three-digit numbers divisible by 7 form an AP. Find the smallest and largest such three-digit numbers.)
Numbers divisible by 7 are 7, 14, 21, 28, ……..
Let’s find the smallest and largest 3-digit number divisible by 7

View solution

Question 4

How many multiples of 4 lie between 10 and 250 ?
(Hint: All multiples of 4 form an AP. Find the smallest and largest multiples of 4 between 10 and 250.)
Multiple of 4 are 4, 8, 12, 16, ….
Let’s find the smallest and largest multiples of 4 between 10 & 250
Smallest multiple
10/4 = 22/4
11/4 = 23/4
𝟏𝟐/𝟒 = 3
∴ Smallest multiple = 12
Largest multiple
250/4 = 622/4
249/4 = 621/4
𝟐𝟒𝟖/𝟒 = 62
∴ Largest multiple = 248
Now, our multiples 7 form an AP
The AP is
12, 16, 20, … 248

View solution

Question 5

Find a GP for which the sum of the first two terms is -4 and the fifth term is 4 times the third term.
Let a be the first term
& r be the common difference

View solution

Question 6

Find all possible ways of expressing 100 as the sum of consecutive natural numbers.
We use the logic of finding Sum of middle numbers
To find 25 + 26 + 27 + ... + 58

View solution

Question 7

The number of bacteria in a certain culture doubles every hour. If there were 30 bacteria present in the culture originally, how many bacteria will be present at the end of 2nd hour, 4th hour and nth hour?
Let’s find Number of bacteria after 1, 2, 3 hours

View solution

Question 8

The sum of 4th and 8th terms of an A.P. is 24 and the sum of the 6th and 10th terms is 44. Find the first three terms of the A.P.
We know that
an = a + (n – 1) d

View solution

Question 9

Find the smallest value of 𝑛 such that the sum of the first 𝑛 natural numbers is greater than 1,000.
Given that
Sum of first n natural numbers > 1,000
𝑆_𝑛>1000
Putting formula
(𝒏(𝒏 + 𝟏))/𝟐>𝟏𝟎𝟎𝟎
Multiplying 2 on right side
𝑛(𝑛 + 1)>2 × 1000
𝒏(𝒏+𝟏) >𝟐𝟎𝟎𝟎

View solution

Question 10

Which term of the GP: 2, 8, 32… is 131072 ? Write the explicit formula as well as the recursive formula for the 𝑛^"th " term.
Given G.P.,
2, 8, 32, ...upto n terms

View solution

Question 11

The sum of the first three terms of a GP is 13/12 and their product is -1. Find the common ratio and the terms.
Let the three terms in G.P. be
𝒂/𝒓, a, ar

View solution

Question 12

If the 4th, 10th and 16th terms of a G.P. are x, y and z, respectively. Prove that x, y, z are in G.P.
For a GP,
We know that
nth term = an = arn – 1

View solution

Question 13

The sum of the first three terms of a geometric progression is 26, and the sum of their squares is 364. Find the terms of the GP.
Let the three terms in G.P. be
𝒂/𝒓, a, ar

View solution

Question 14

Suppose P_1=1,P_2=2 and for 𝑛>2,P_n=P_1+P_2+⋯+P_(n−1)+1. Find the values of P_1,P_2,…,P_8. Can you find a simpler recursive formula for P_n? Can you give an explicit formula?
Let’s do it one by one

View solution

Question 15

Suppose W_1=1,〖" " W〗_2=2 and for 𝑛>2,〖" " W〗_n=W_1+W_2+⋯+W_(n−2)+2. Find the values of W_1,〖" " W〗_2,…,〖" " W〗_8. Do you recognise this sequence?
Finding the values of 𝑾_𝟏 to 𝑾_𝟖
Let's calculate carefully:
𝑊_1=𝟏 (Given)
𝑊_2=𝟐 (Given)
𝑊_3=𝑊_1+2=1+2=𝟑
𝑊_4=𝑊_1+𝑊_2+2=1+2+2=𝟓
𝑊_5=𝑊_1+𝑊_2+𝑊_3+2=1+2+3+2=𝟖
𝑊_6=(1+2+3+5)+2=𝟏𝟑
𝑊_7=(1+2+3+5+8)+2=𝟐𝟏
𝑊_8=(1+2+3+5+8+13)+2=𝟑𝟒
The first 8 values are: 1,2,3,5,8,13,21,34 2. Do you recognize this sequence?
Yes. This is the Fibonacci sequence. Even though the problem gave a complicated, drawn-out recursive rule involving adding 2 , the result is identical to the standard Fibonacci rule where every number is simply the sum of the two numbers right before it ( 𝑊_𝑛=𝑊_(𝑛−1)+𝑊_(𝑛−2) ).

View solution

Why Learn This With Teachoo?

Predicting What Comes Next: Exploring Sequences and Progressions is Chapter 8 of NCERT Class 9 Ganita Manjari Part 1. It develops explicit and recursive sequence rules, the Virahāṅka–Fibonacci sequence, arithmetic progressions, geometric progressions, sums and visual models. Students learn to distinguish additive and multiplicative patterns and express the nth term of a progression. Teachoo provides explanations and solutions for Exercise Sets 8.1 to 8.3 and the end-of-chapter exercises.

Sequences, explicit rules and recursive rules

A sequence is an ordered list of numbers or objects generated according to a rule. Position matters. An explicit rule gives a term directly from its position n, while a recursive rule defines a term using one or more earlier terms and requires starting values.

For example, a sequence may have explicit rule aₙ = 3n + 1. A recursive description could state a₁ = 4 and aₙ = aₙ₋₁ + 3. Both produce the same terms but reveal different aspects of the pattern.

The Virahāṅka–Fibonacci sequence is recursive: each new term is obtained from the preceding terms according to its established rule. The chapter connects this pattern with Indian mathematical history, arrangement problems and natural structures.

Arithmetic progressions

An arithmetic progression (AP) has a constant difference d between consecutive terms. If the first term is a, its nth term is

aₙ = a + (n − 1)d.

Positive d gives growth, negative d gives decay and d = 0 gives a constant sequence. Visualising an AP through dot arrangements or graphs reveals constant additive change.

The sum of the first n natural numbers, n(n + 1)/2, is studied through pairing and geometric arrangements. These methods show how a sum formula can emerge from structure rather than memorisation.

Geometric progressions

A geometric progression (GP) has a constant non-zero ratio r between consecutive terms. Its nth term is

aₙ = arⁿ⁻¹.

Geometric growth or decay is multiplicative. Fractals can generate GP sequences when the number, length or area of pieces changes by a fixed factor at every stage. Visualising a GP helps students understand why its graph and long-term behaviour differ from an AP.

Topics covered on Teachoo

Teachoo includes:

  • definition of sequences;

  • explicit rules;

  • recursive rules;

  • Virahāṅka–Fibonacci sequence;

  • Exercise Set 8.1;

  • arithmetic progressions;

  • visualising an AP;

  • sum of the first n natural numbers;

  • Exercise Set 8.2;

  • geometric progressions;

  • fractals as GP sequences;

  • visualising a GP;

  • Exercise Set 8.3; and

  • end-of-chapter exercise solutions.

Learning outcomes

Students should be able to generate terms from explicit and recursive rules, write a rule from a pattern and identify the information needed to define a sequence uniquely. They should recognise APs and GPs, find a common difference or ratio and use nth-term formulas. They should connect visual patterns with progressions and explain the distinction between linear additive growth and multiplicative geometric growth.

Why is this chapter important?

Sequences model repeated change in finance, population, measurement, computer algorithms and natural patterns. APs prepare students for Class 10 arithmetic progressions, while GPs introduce exponential behaviour and compounding. Explicit and recursive rules also support functions, coding and mathematical induction.

How Teachoo helps

Teachoo separates general sequence language from AP and GP methods. Begin by listing consecutive differences and ratios; do not decide from visual impression alone. Once the type is known, identify a, d or r and substitute into the correct nth-term formula.

For visual patterns, record the stage number and counted quantity in a table, then test the proposed rule on an unseen stage. For recursion, state every required initial value. Compare your method with Teachoo’s solution after the rule has been independently formed.

Common mistakes to avoid

Do not confuse term number n with the term’s value. In an AP, d is found by subtraction in a consistent order; in a GP, r is found by division in a consistent order. A sequence can match both an AP and GP only in special constant cases. A recursive rule without sufficient starting terms is incomplete.

Quick revision checklist

Generate terms from two explicit and two recursive rules, stating all initial values. For unfamiliar sequences, calculate both consecutive differences and ratios before classifying them. Find missing terms and nth terms in an AP and GP, and verify by substitution. Derive the sum of the first n natural numbers through pairing or a visual arrangement. Finally, model one fractal stage count and explain why its pattern is geometric rather than arithmetic.

Approach to pattern questions

Several different rules can reproduce a short finite list, so a guessed continuation is not automatically unique. Use the context, diagram or stated construction rule. Define what the stage number represents, make a table and test the proposed formula beyond the examples used to create it. A full answer describes both the numerical rule and the mechanism that produces it.

Deeper reasoning and concept connections

Study Predicting What Comes Next: Exploring Sequences and Progressions (Ganita Manjari Part 1) through comparison and justification. Place two related examples side by side, identify the decisive difference and explain why one method works in each case. Then create a new example and a deliberate non-example. This forces the definition to do real work and exposes gaps that passive reading hides.

Students should also practise reversing questions. After solving for an answer, ask what question could have produced it, whether more than one answer is possible and which extra condition would make the result unique. Reverse reasoning develops flexibility and is especially useful for missing-value, assertion–reason and error-analysis questions. The goal is to understand the network of ideas, not merely the order of a textbook solution.

How to solve unfamiliar and competency-based questions

Begin by separating facts from conclusions. Facts are given by the question or a known property; conclusions must be derived. Draw or rewrite the problem so each fact has a visible place. If several methods are possible, prefer the one with fewer assumptions and an easy final check. Record intermediate results rather than doing everything mentally.

Competency questions often change context without changing mathematics. Replace names and story details with variables, shapes, sets or data values. After solving, restore the context and check feasibility: counts should be whole where required, lengths and areas should have suitable units, probabilities should lie between 0 and 1, and constructed figures should satisfy every stated condition.

What complete mastery looks like

For Predicting What Comes Next: Exploring Sequences and Progressions (Ganita Manjari Part 1), a student should be able to define the central ideas in simple language, recognise them in different representations, solve routine questions accurately and explain the method used. They should also be able to correct a flawed solution, create an example satisfying given conditions and combine two ideas from the chapter in one problem. A reliable mastery test is to solve one direct question, one application question and one reasoning question without looking at notes, then explain all three aloud or in writing.

Keep a compact error log with four labels: concept, interpretation, calculation and presentation. Reattempt each error after a gap instead of rereading the answer immediately. Improvement comes from correcting the decision that caused the mistake, not from repeating questions whose method is already known.

Additional frequently asked questions

What should a student know before starting Predicting What Comes Next: Exploring Sequences and Progressions (Ganita Manjari Part 1)?

Revise the definitions, number operations, diagrams or notation used at the beginning of the chapter. The prerequisite list should be short: if an earlier skill blocks progress, repair that skill with two or three focused questions and return to the chapter.

How can a student check an answer in Predicting What Comes Next: Exploring Sequences and Progressions (Ganita Manjari Part 1)?

Use an independent check whenever possible: substitute the result, reverse the operation, estimate its size, compare it with the figure, test a simpler case or solve using another representation. A check should examine the mathematical condition, not merely repeat the same arithmetic.

How many questions are enough for strong preparation?

There is no fixed number. Stop counting questions and track coverage: every concept, every standard method, at least one mixed problem, one competency-based problem and every previously incorrect type should be solved independently. Ten varied, analysed questions are more valuable than fifty copied solutions.

How should Teachoo solutions be used without becoming dependent on them?

Attempt the question first and mark the exact step where progress stops. Read only enough of the solution to repair that step, close it and restart the question. Finally, solve a similar problem without help. This turns a solution into feedback rather than a substitute for thinking.

Frequently asked questions

What is the difference between an explicit and recursive rule?

An explicit rule calculates a term directly from its position; a recursive rule calculates it from earlier terms.

How do I identify an arithmetic progression?

Check whether consecutive terms have the same difference.

How do I identify a geometric progression?

Check whether consecutive non-zero terms have the same ratio.

Determine whether the pattern changes by addition or multiplication, then build the rule and test it beyond the given terms.