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Ex 8.2, 1
Last updated at June 9, 2026 by Teachoo
Class 9
Chapter 8 - Predicting What Comes Next: Exploring Sequences & Progress
- Definition
- Explicit Rule for a Sequence
- Recursive Rule for a Sequence
- Virahānka–Fibonacci sequence
- Exercise Set 8.1
- Arithmetic Progressions
- Visualising an AP
- Sum of the First n Natural Numbers
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Exercise Set 8.2
- Geometric Progressions
- Fractals as a GP Sequence
- Visualising a GP
- Exercise Set 8.3
- End-of-Chapter Exercises
Transcript
Ex 8.2, 1 Find the 10th and 26th terms of the AP 3, 8, 13, 18,…. Given AP 3, 8, 13,18, … Here, First term = a = 3 Common difference = d = 8 – 3 = 5 We need to find the 10th and 26th term So, we use the formula an = a + (n – 1) d Now, 10th term = a10 = a + (10 – 1)d = 3 + 9 × 5 = 3 + 45 = 48 And, 26th term = a26 = a + (26 – 1)d = 3 + 25 × 5 = 3 + 125 = 128
