Check sibling questions

Misc 17 - Find derivative: sin x + cos x / sin x - cos x

Misc 17 - Chapter 13 Class 11 Limits and Derivatives - Part 2
Misc 17 - Chapter 13 Class 11 Limits and Derivatives - Part 3
Misc 17 - Chapter 13 Class 11 Limits and Derivatives - Part 4

This video is only available for Teachoo black users


Transcript

Misc 17 Find the derivative of the following functions (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers): sin⁡〖x + cos⁡x 〗/sin⁡〖x − cos⁡x 〗 Let f (x) = sin⁡〖x + cos⁡x 〗/sin⁡〖x − cos⁡x 〗 Let u = sin x + cos x & v = sin x – cos x ∴ f(x) = 𝑢/𝑣 So, f’(x) = (𝑢/𝑣)^′ Using quotient rule f’(x) = (𝑢^′ 𝑣 −〖 𝑣〗^′ 𝑢)/𝑣^2 Finding u’ & v’ u = sin x + cos x u’ = (sin x + cos x)’ = (sin x)’ + (cos x)’ = cos x – sin x v = sin x – cos x v’= (sin x – cos x)’ = (sin x)’ – (cos x)’ = cos x – ( – sin x) = cos x + sin x Derivative of sin x = cos x Derivative of cos x = – sin x Now, f’(x) = (𝑢/𝑣)^′ = (𝑢^′ 𝑣 −〖 𝑣〗^′ 𝑢)/𝑣^2 = ( (cos⁡〖𝑥 −〖 sin〗⁡〖𝑥) (sin⁡〖𝑥 −〖 cos〗⁡〖𝑥) − (cos⁡〖𝑥 +〖 sin〗⁡〖𝑥) (sin⁡〖𝑥 +〖 cos〗⁡〖𝑥)〗 〗 〗 〗 〗 〗 〗 〗)/〖(sin⁡〖x −co𝑠 𝑥〗)〗^2 = (−(sin⁡〖𝑥 −〖 cos〗⁡〖𝑥) (sin⁡〖𝑥 −〖 cos〗⁡〖𝑥) − (sin⁡〖𝑥 + cos⁡〖𝑥) (sin⁡〖𝑥 +〖 cos〗⁡〖𝑥)〗 〗 〗 〗 〗 〗 〗 〗)/〖(sin⁡〖x − co𝑠 𝑥〗)〗^2 = (〖−(sin⁡〖x − co𝑠 𝑥〗)〗^2 − 〖(sin⁡〖x + co𝑠 𝑥〗)〗^2)/〖(sin⁡〖x − co𝑠 𝑥〗)〗^2 Using (a + b)2 = a2 + b2 + 2ab (a – b)2 = a2 + b2 – 2ab = ( − [(sin2⁡〖𝑥 +〖 cos2〗⁡〖𝑥 − 2 sin⁡〖𝑥 〖 cos〗⁡〖𝑥) + (𝑠𝑖𝑛2𝑥 + 𝑐𝑜𝑠2𝑥 + 2𝑠𝑖𝑛𝑥 cos⁡〖𝑥)]〗 〗 〗 〗 〗)/〖(sin⁡〖x − co𝑠 𝑥〗)〗^2 = ( − ( 2𝑠𝑖𝑛2𝑥 + 2𝑐𝑜𝑠2𝑥 − 0))/〖(sin⁡〖x − co𝑠 𝑥〗)〗^2 = ( −2 (𝒔𝒊𝒏𝟐𝒙 + 𝒄𝒐𝒔𝟐𝒙))/〖(sin⁡〖x − co𝑠 𝑥〗)〗^2 = ( −2 (𝟏))/〖(sin⁡〖x − co𝑠 𝑥〗)〗^2 = ( −𝟐 )/〖(𝒔𝒊𝒏⁡〖𝐱 − 𝒄𝒐𝒔 𝒙〗)〗^𝟐 (Using sin 2 x + cos 2 x = 1)

Davneet Singh's photo - Teacher, Engineer, Marketer

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.