We have seen that the repeating block of 1/7 is a cyclic number - Exercise Set 3.5

part 2 - Ex 3.5, 5 - Exercise Set 3.5 - Chapter 3 Class 9 - The World of Numbers (Ganita Manjari I) - Class 9
part 3 - Ex 3.5, 5 - Exercise Set 3.5 - Chapter 3 Class 9 - The World of Numbers (Ganita Manjari I) - Class 9

part 4 - Ex 3.5, 5 - Exercise Set 3.5 - Chapter 3 Class 9 - The World of Numbers (Ganita Manjari I) - Class 9

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Transcript

Ex 3.5, 5 We have seen that the repeating block of 1/7 is a cyclic number. Try to find more numbers (n) whose reciprocals (1/𝑛) produce decimals with repeating blocks that are cyclic. We saw that 1/7 produces the cyclic block 142857. Since 7 is a prime number, lets try others Let’s try 𝟏/πŸπŸ• Dividing 1 by 17Thus, For n = 17 1/17 = 0.(πŸŽπŸ“πŸ–πŸ–πŸπŸ‘πŸ“πŸπŸ—πŸ’πŸπŸπŸ•πŸ”πŸ’πŸ•) Μ… ∴ The repeating block of digits after decimal point are 16 For n = 19 1/19 = 0.(πŸŽπŸ“πŸπŸ”πŸ‘πŸπŸ“πŸ•πŸ–πŸ—πŸ’πŸ•πŸ‘πŸ”πŸ–πŸ’πŸπŸ) Μ… ∴ The repeating block of digits after decimal point are 18 For n = 23 1/23 = 0.(πŸŽπŸ’πŸ‘πŸ’πŸ•πŸ–πŸπŸ”πŸŽπŸ–πŸ”πŸ—πŸ“πŸ”πŸ“πŸπŸπŸ•πŸ‘πŸ—πŸπŸ‘) Μ… ∴ The repeating block of digits after decimal point are 22

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