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Question 2 - Page 171 - Areas in Real Life - Chapter 7 Class 8 - Area (Ganita Prakash II)
Last updated at March 16, 2026 by Teachoo
Areas in Real Life
Question 1 - Page 170
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Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 7 Class 8 - Area (Ganita Prakash II)
- Area of Rectangle and Square
- Perimeter vs Area
- Figure it out - Page 150-152
- Area of Triangle
- Applications of Area of Triangle Formula
- Triangles between Parallel Lines with a Common Base
- Figure it out - Page 157-159
- Area of any Polygon
- Figure it out - Page 160
- Area of Parallelogram
- Area of Rhombus
- Area of Trapezium
- Figure it out - Page 169-170
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Areas in Real Life
Transcript
Question 2 - Page 171 Convert 161.29 cm2 to in2.We know that 1 in2 = 6.4516 cm2 6.4516 cm2 = 1 in2 64516/10000 cm2 = 1 in2 1 cm2 = ๐๐๐๐๐/๐๐๐๐๐ in2 Now, 161.29 cm2 = 161.29 ร 10000/64516 in2 = ๐๐๐๐๐/๐๐๐ ร ๐๐๐๐๐/๐๐๐๐๐ in2 = 16129/64516 ร 10000/100 in2 = 16129/64516 ร 10000/100 in2 = 1/4 ร 100 in2 = 25 in2
