Area of Parallelogram - from First Principles - Teachoo Class 8 - Area of Parallelogram

part 2 - Area of Parallelogram - Area of Parallelogram - Chapter 7 Class 8 - Area (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Area of Parallelogram - Area of Parallelogram - Chapter 7 Class 8 - Area (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 4 - Area of Parallelogram - Area of Parallelogram - Chapter 7 Class 8 - Area (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Transcript

Area of ParallelogramLet’s Consider a Parallelogram ABCD, with height AX To find Area of Parallelogram, we use two methods Converting it into Two Triangles and finding Area Transforming it into a Rectangle Let’s Transfrorm it into a Rectangle We converted Parallelogram ABCD into Rectangle AXBY The process of cutting a figure into pieces and rearranging them to get a different figure of equal area is called dissection Since Area of Paralleogram ABCD = Area of Rectangle ABXY And, Rectangle ABXY has sides Base and Height We can write Area of the parallelogram ABCD = Area of the rectangle ABYX. = AX × XY Since DX = CY, We can write DX + XC = CY + XC CD = YX Thus, our formula for Parallelogram becomes Area of the parallelogram ABCD = AX × CD Generally we can write Area of Parallelogram = Base × Height Generally we can write Area of Parallelogram = Base × Height

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.