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Example 15 - Find hyperbola foci (0,3), vertices (0, 11/2) - Hyperbola

Example 15 - Chapter 11 Class 11 Conic Sections - Part 2
Example 15 - Chapter 11 Class 11 Conic Sections - Part 3

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Example 15 Find the equation of the hyperbola with foci (0, 3) and vertices 0, 11 2 . Since, foci are on the y-axis So required equation of hyperbola is = 1 We know that Vertices = (0, a) Given vertices are 0, 11 2 So, (0, a) = 0, 11 2 a = 11 2 a2 = We know that foci = (0, c) Given foci = (0, 3) So c = 3 We know that c2 = a2 + b2 32 = 11 4 + b2 9 11 4 + b2 36 11 4 = b2 25 4 = b2 b2 = Equation of hyperbola is 2 2 2 2 = 1 Putting values of a2 & b2 2 11 4 2 25 4 = 1 4 2 11 4 2 25 = 1 100 2 44 2 275 = 1 100y2 44x2 = 275

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.