Example 15 - Find hyperbola foci (0,3), vertices (0, 11/2) - Hyperbola

Slide42.JPG
Slide43.JPG

  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise
Ask Download

Transcript

Example 15 Find the equation of the hyperbola with foci (0, 3) and vertices 0, 11 2 . Since, foci are on the y-axis So required equation of hyperbola is = 1 We know that Vertices = (0, a) Given vertices are 0, 11 2 So, (0, a) = 0, 11 2 a = 11 2 a2 = We know that foci = (0, c) Given foci = (0, 3) So c = 3 We know that c2 = a2 + b2 32 = 11 4 + b2 9 11 4 + b2 36 11 4 = b2 25 4 = b2 b2 = Equation of hyperbola is 2 2 2 2 = 1 Putting values of a2 & b2 2 11 4 2 25 4 = 1 4 2 11 4 2 25 = 1 100 2 44 2 275 = 1 100y2 44x2 = 275

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.