Example, 11 - Chapter 11 Class 11 Conic Sections (Term 2)
Last updated at May 29, 2018 by Teachoo
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Last updated at May 29, 2018 by Teachoo
Example, 11 Find the equation of the ellipse whose vertices are (± 13, 0) and foci are (± 5, 0) Given vertices are (± 13, 0) The given vertices are of the form (±a, 0) Hence the major axis is along x-axis & Equation of ellipse is of the form 𝑥2𝑎2 + 𝑦2𝑏2 = 1 From (1) & (2) a = 13 Also given coordinate of foci = (±5, 0) We know that foci = (± c, 0) So c = 5 We know that c2 = a2 − b2 (5) 2 = (13) 2 − b2 b2 = (13) 2 − (5) 2 b2 = 169 − 25 b2 = 144 Equation of ellipse is 𝑥2𝑎2 + 𝑦2𝑏2 = 1 Putting value 𝒙𝟐𝟏𝟔𝟗 + 𝒚𝟐𝟏𝟒𝟒 = 1