Example 7 - Chapter 11 Class 11 Conic Sections (Term 2)
Last updated at Feb. 6, 2020 by
Transcript
Example 7 Find the equation of the parabola with vertex at (0, 0) & focus at (0, 2). Since focus (0, 2) lie on the y-axis Hence, Equation of parabola is either x2 = 4ay & x2 = −4ay Since focus has positive y – co-ordinate So, we have to use equation x2 = 4ay Coordinate of focus = (0, a) (0, a) = (0, 2) a = 2 Required equation is x2 = 4ay x2 = 4 × 2y x2 = 8y
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Example 13 Important
Example 14 (i)
Example 14 (ii) Important
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Example, 19 Important
Chapter 11 Class 11 Conic Sections (Term 2)
Serial order wise
- Ex 11.1
- Ex 11.2
- Ex 11.3
- Ex 11.4
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Examples
- Miscellaneous
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.
