Example 6 - Chapter 11 Class 11 Conic Sections (Term 2)
Last updated at Feb. 6, 2020 by Teachoo
Examples
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Example 2
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Example 4 Important
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Example 6 Important You are here
Example 7 Important
Example 8 Important
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Example 13 Important
Example 14 (i)
Example 14 (ii) Important
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Example, 19 Important
Chapter 11 Class 11 Conic Sections (Term 2)
Serial order wise
- Ex 11.1
- Ex 11.2
- Ex 11.3
- Ex 11.4
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Examples
- Miscellaneous
Transcript
Example 6 Find the equation of the parabola with focus (2, 0) and directrix x = –2. Since focus lies on x-axis Hence equation is either y2 = 4ax or y2 = −4ax Now, focus has positive x co-ordinate So, we have to use equation y2 = 4ax Coordinates of focus = (a, 0) (2, 0) = (a, 0) Hence a = 2 Required equation is y2 = 4ax y2 = 4 × 2 × x y2 = 8x
