Example 8 - Find equation of parabola symmetric about y-axis - Examples

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  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise

Transcript

Example 8 Find the equation of the parabola which is symmetric about the y-axis, and passes through the point (2, 3). Since the parabola is symmetric about y-axis Equation is of the form x2 = 4ay or x2 = 4ay Now plotting point (2, 3) on graph Since (2,-3) lies in fourth quadrant So the parabola will be of the form Hence we use equation x2 = 4ay. Now parabola passes through (2, 3) Putting x = 2, y = 3 in equation 22 = 4 a 3 4 = 12a 4 12 = a 1 3 = a a = Equation of parabola is x2 = 4ay x2 = y

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