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Question 1 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
Last updated at February 23, 2026 by Teachoo
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
- Doubling a square
- Halving a square
- Hypotenuse of an Isosceles Right Triangle
- Decimal Representation of β2
- Figure it out - Page 39, 40
- Formula for Hypotenuse of an Isosceles Right Triangle
- Combining Two squares
- BaudhΔyanaβs Theorem on Right-angled triangles
- Pythagorean triples
- Figure it out - Page 50
- A Long-Standing Open Problem
- Further Applications of the BaudhΔyana - Pythagoras Theorem
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Figure it out - Page 52, 53, 54
Transcript
Question 1 Find the diagonal of a square with sidelength 5 cm.Here, Diagonal is BD From Pythagoras Theorem Hypotenuse2 = Base2 + Height2 BD2 = AB2 + AD2 BD2 = 52 + 52 BD2 = 25 + 25 BD2 = 50 BD = βππ BD = β(2 Γ 25) BD = β(2 Γ 5^2 ) BD = β2 Γ β(5^2 ) BD = β2 Γ 5 BD = πβπ Thus, Diagonal is of length βππ cm or πβπ cm
