Example 10 - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II)

Transcript

Example 10 A TV is bought at a price of ₹21,000. After 1 year, the value of the TV depreciates by 5%. Find the value of the TV after one year.TV was bought for ₹ 21000 So, P = ₹ 21000 Also, TV depreciated by 5% in one year Depreciated means value is decreased So, we Put a Minus sign in rate Rate = −5% Also, Rate is compounded So we use the formula A = P (𝟏+𝑹)^𝒕 Here, P = 21000 R = –5 % = (−𝟓)/𝟏𝟎𝟎 T = Number of years = 1 Putting Values in Formula A = 21000 (𝟏+((−𝟓))/𝟏𝟎𝟎)^𝟏 A = 21000 (1−5/100) A = 21,000 × (1−1/20) A = 21,000 × ((20 − 1)/20) A = 21,000 × 𝟏𝟗/𝟐𝟎 A = 2100/2 × 19 A = 1050 × 19 A = 19950 Value of the TV after one year = ₹ 19,950