Example 6 (Page 17) - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II)

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Example 6 (Page 17) Shyamala had procured decorative vases at ₹2650 per piece. One of the pieces was slightly damaged. She decides to sell it at a loss of 18%. How much will she get by selling this piece?Given Cost Price = ₹ 2650 Loss Percentage = 18% We need to find Selling Price Now, Loss Percentage = 𝑳𝒐𝒔𝒔/(𝑪𝒐𝒔𝒕 𝑷𝒓𝒊𝒄𝒆) × 100 Loss Percentage = (𝐶𝑜𝑠𝑡 𝑃𝑟𝑖𝑐𝑒 − 𝑆𝑒𝑙𝑙𝑖𝑛𝑔 𝑃𝑟𝑖𝑐𝑒)/(𝐶𝑜𝑠𝑡 𝑃𝑟𝑖𝑐𝑒) × 100 Putting values 18 = (𝑺𝒆𝒍𝒍𝒊𝒏𝒈 𝑷𝒓𝒊𝒄𝒆 − 𝟐𝟔𝟓𝟎)/𝟐𝟔𝟓𝟎 × 100 18 = (Selling Price – 2650) × 100/2650 18 × 2650/100 = Selling Price – 2650 Selling Price – 2650 = 18 × 𝟐𝟔𝟓𝟎/𝟏𝟎𝟎 Selling Price – 2650 = 18 × 265/10 Selling Price – 2650 = 18 × 53/2 Selling Price – 2650 = 9 × 53 Selling Price – 2650 = 477 Selling Price = 477 + 2650 Selling Price = 2173 Thus, selling price is ₹ 2173