[Ganita Prakash Class 8] Find the missing numbers. The first problem - Figure it out - Page 12, 13, 14

part 2 - Question 1 - Figure it out - Page 12, 13, 14 - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question 1 - Figure it out - Page 12, 13, 14 - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 4 - Question 1 - Figure it out - Page 12, 13, 14 - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 5 - Question 1 - Figure it out - Page 12, 13, 14 - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question 1 Find the missing numbers. The first problem has been worked outLet’s check the Maths Left Side We see 5 blocks make up 100%. This means each block is πŸπŸŽπŸŽΓ·πŸ“=𝟐𝟎%. Right Side We see the same 5 blocks. The bracket showing 60 covers 4 of those blocks. If 4 blocks =60, then 1 block =πŸ”πŸŽΓ·πŸ’=πŸπŸ“. Thus, the total (all 5 blocks) would be 15 Γ— 5=75 Check: The number at the end is indeed 75 !If 4 blocks =60, then 1 block =πŸ”πŸŽΓ·πŸ’=πŸπŸ“. Thus, the total (all 5 blocks) would be 15 Γ— 5=75 Check: The number at the end is indeed 75 ! Question 1 Find the missing numbers. The first problem has been worked outLeft Side There are 10 blocks total making 100%. So, 1 block =10%. The question mark is pointing to the first block, so ?=𝟏𝟎%. Right Side The bracket showing πŸ—πŸŽ covers 9 blocks. If 9 blocks =90, then 1 block =90Γ·9=10. The question mark covers roughly the first 6 blocks. So, 6 blocks Γ— 𝟏𝟎=πŸ”πŸŽ Thus ?=πŸ”πŸŽ Question 1 Find the missing numbers. The first problem has been worked outLeft Side There are 4 blocks making 100%. So, 1 block =25%. The question mark covers 1 blocks. So, ?=πŸ•πŸ“% Right Side The total is πŸπŸ’πŸŽ. Since 4 blocks =140, then 1 block =πŸπŸ’πŸŽΓ·πŸ’=πŸ‘πŸ“ The bottom arrow covers 3 blocks So, πŸ‘ Γ— πŸ‘πŸ“=πŸπŸŽπŸ“ Thus ?=πŸπŸŽπŸ“

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.