Ex 10.4, 1 - Chapter 10 Class 11 Conic Sections

Last updated at December 16, 2024 by

Ex 10.4, 1 - Find foci, vertices of hyperbola x^2 / 16 - y^2 / 9 = 1 - Ex 10.4 part 2 - Ex 10.4, 1 - Ex 10.4 - Serial order wise - Chapter 10 Class 11 Conic Sections part 3 - Ex 10.4, 1 - Ex 10.4 - Serial order wise - Chapter 10 Class 11 Conic Sections

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Ex 10.4, 1 Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola x2 16 - y2 9 = 1 Given equation is 2 16 2 9 = 1 The above equation is of the form 2 2 2 2 = 1 So axis of hyperbola is x-axis , Comparing (1) & (2) a2 = 16 a = 4 & b2 = 9 b = 3 Now, c2 = a2 + b2 c2 = 16 + 9 c2 = 25 c = 5 Co-ordinate of foci = ( c, 0) = ( 5, 0) Hence co-ordinates of foci are (5, 0) & ( 5, 0) Co-ordinate of vertices = ( a, 0) = ( 4,0) So, co-ordinates of vertices are (4, 0) & ( 4, 0) Eccentricity = e = = 5 4 Latus rectum = 2 2 = 2(9) 4 = 9 2

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo