[Class 7] Construct a Triangle for the Measurements: 75°, 5 cm, 75° - Constructing Triangle when 2 Angles and the Included Side are given

part 2 - Question 1 (a) - Figure it out - Page 162 - Constructing Triangle when 2 Angles and the Included Side are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Question 1 (a) - Figure it out - Page 162 - Constructing Triangle when 2 Angles and the Included Side are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT) part 4 - Question 1 (a) - Figure it out - Page 162 - Constructing Triangle when 2 Angles and the Included Side are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT) part 5 - Question 1 (a) - Figure it out - Page 162 - Constructing Triangle when 2 Angles and the Included Side are given - Chapter 7 Class 7 - A tale of three Intersecting Lines (Ganit Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)

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Transcript

Question 1 (a) - Figure it out - Page 162 Construct triangles for the following measurements: (a) 75°, 5 cm, 75° First, we draw a rough figure We take the side as base Now, let’s construct it Steps of construction 1. Draw a line segment AB of length 5 cm 2. Since ∠ A = 75° Using protractor, we draw 75° from point A Note: We read the blue mark on protractor 2. Since ∠ B = 75° Using protractor, we draw 75° from point B Note: We read the black mark on protractor 4. The intersection point is Point C. We label the sides Thus, Δ ABC is the required triangle

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