[Class 7] Find the area of a rectangle of sides 3 3/4 ft and 9 3/5 ft - Figure it out - Page 183, 184

part 2 - Question 3 - Figure it out - Page 183, 184 - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Question 3 - Figure it out - Page 183, 184 - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)

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Question 3 Find the area of a rectangle of sides 3 3/4 ft and 9 3/5 ft. First, we convert length and breadth to proper fractions Now, Length = 9 3/5 ft = 9+3/5 = (9 Ɨ 5 + 3)/5 = (45 + 3)/5 = šŸ’šŸ–/šŸ“ ft And, Breadth = 9 3/5 ft = 9+3/5 = (9 Ɨ 5 + 3)/5 = (45 + 3)/5 = šŸ’šŸ–/šŸ“ ft Breadth = 3 cm Area of rectangle = Length Ɨ Breadth = 5.7 cm Ɨ 3 cm = 57/10 Ɨ 3 Ɨ (cm Ɨ cm) Area of rectangle = Length Ɨ Breadth = šŸ’šŸ–/šŸ“ ft Ɨ šŸšŸ“/šŸ’ ft = 48/5 Ɨ15/4 Ɨ (ft Ɨ ft) = 48/5 Ɨ15/4 Ɨ ft2 = (šŸ’šŸ– Ɨ šŸšŸ“)/(šŸ“ Ɨ šŸ’) = (48 Ɨ 3)/(1 Ɨ 4) = (12 Ɨ 3)/(1 Ɨ 1) = 36 ft2 ∓ The area of the rectangle is 36 square feet.

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