Figure it out - Page 183, 184
Figure it out - Page 183, 184
Last updated at July 21, 2026 by Teachoo
Transcript
Question 3 Find the area of a rectangle of sides 3 3/4 ft and 9 3/5 ft. First, we convert length and breadth to proper fractions Now, Length = 9 3/5 ft = 9+3/5 = (9 Ć 5 + 3)/5 = (45 + 3)/5 = šš/š ft And, Breadth = 9 3/5 ft = 9+3/5 = (9 Ć 5 + 3)/5 = (45 + 3)/5 = šš/š ft Breadth = 3 cm Area of rectangle = Length Ć Breadth = 5.7 cm Ć 3 cm = 57/10 Ć 3 Ć (cm Ć cm) Area of rectangle = Length Ć Breadth = šš/š ft Ć šš/š ft = 48/5 Ć15/4 Ć (ft Ć ft) = 48/5 Ć15/4 Ć ft2 = (šš Ć šš)/(š Ć š) = (48 Ć 3)/(1 Ć 4) = (12 Ć 3)/(1 Ć 1) = 36 ft2 ā“ The area of the rectangle is 36 square feet.