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Finding sum from nth number
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Finding sum from nth number
Last updated at May 29, 2023 by Teachoo
Question 9 Find the sum to n terms of the series whose nth terms is given by n2 + 2n Given an = n2 + 2n Now, sum of n terms is Now, = 2 + 4 + 8 + + 2n This is GP with first term A = 2 & common ratio R = 4/2 = 2 We know that sum of n term in GP Sn = ( (R^n 1))/(R 1) Putting values Now from (1) Putting values = (n(n+1)(2n+1))/6 + 2(2n 1) Thus, the required sum is (n(n+1)(2n+1))/6 + 2(2n 1)