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Example 11 - Chapter 8 Class 11 Sequences and Series
Last updated at May 29, 2023 by Teachoo
Geometric Progression(GP): Statement
Chapter 8 Class 11 Sequences and Series
Concept wise
- Finding Sequences
- Arithmetic Progression (AP): Formulae based
- Arithmetic Progression (AP): Statement
- Arithmetic Progression (AP): Calculation based/Proofs
- Inserting AP between two numbers
- Arithmetic Mean (AM)
- Geometric Progression(GP): Formulae based
-
Geometric Progression(GP): Statement
- Geometric Progression(GP): Calculation based/Proofs
- Inserting GP between two numbers
- Geometric Mean (GM)
- AM and GM (Arithmetic Mean And Geometric mean)
- AP and GP mix questions
- Finding sum from series
- Finding sum from nth number
Transcript
Example 11, A person has 2 parents, 4 grandparents, 8 great grandparents, and so on. Find the number of his ancestors during the ten generations preceding his own. The number of ancestors are 2,4,8,16, β¦ It is a G.P. since, 4/2 = 2 8/4 = 2 β΄ Common ratio = 2 First term = a = 2 & number of generations (n) = 10 We have to find the number of his ancestors during the ten generations preceding his own, i.e. S10 As r > 1 Sum of n terms in GP = (a(π^π β 1))/(r β 1) i.e. Sn = (a(π^π β 1))/(r β 1) Putting values of a=2, r=2, & n=10 S10 = (2(210 β 1))/(2 β 1) S10 = (2(210 β 1))/1 S10 = (210 + 1 β 2) S10 = 211 β 2 S10 = 2048 β 2 S10 = 2046 Hence, the number of ancestors preceding the person is 2046.
