Question 1 - Page 55 - Hundredth - Chapter 3 Class 7 - A peek beyond the Point (Ganita Prakash)

Transcript

Question 1 – Page 55 (a) In each group, identify the longest and the shortest lengths. Mark each length on the scale. Converting them into same denominators 𝟑/𝟏𝟎=3/10 ×10/10=𝟑𝟎/𝟏𝟎𝟎 𝟑/𝟏𝟎𝟎 𝟑𝟑/𝟏𝟎𝟎 Since denominator is same, we compare numerators Therefore, Shortest length = 𝟑/𝟏𝟎𝟎 Longest length = 𝟑𝟑/𝟏𝟎𝟎 Question 1 – Page 55 (b) In each group, identify the longest and the shortest lengths. Mark each length on the scale. Converting them into same denominators 𝟑 𝟏/𝟏𝟎=31/10 𝟑𝟎/𝟏𝟎 𝟏 𝟑/𝟏𝟎=𝟏𝟑/𝟏𝟎 Since denominator is same, we compare numerators Therefore, Shortest length = 𝟏 𝟑/𝟏𝟎 Longest length = 𝟑 𝟏/𝟏𝟎 Question 1 – Page 55 (c) In each group, identify the longest and the shortest lengths. Mark each length on the scale. Converting them into same denominators 𝟒𝟓/𝟏𝟎𝟎 𝟓𝟒/𝟏𝟎𝟎 𝟓/𝟏𝟎=5/10 ×10/10=𝟓𝟎/𝟏𝟎𝟎 𝟒/𝟏𝟎=4/10 ×10/10=𝟒𝟎/𝟏𝟎𝟎 Since denominator is same, we compare numerators Therefore, Shortest length = 𝟒/𝟏𝟎 Longest length = 𝟓𝟒/𝟏𝟎𝟎 Question 1 – Page 55 (d) In each group, identify the longest and the shortest lengths. Mark each length on the scale. Converting them into same denominators 𝟑 𝟔/𝟏𝟎=36/10=36/10 ×10/10=𝟑𝟔𝟎/𝟏𝟎𝟎 𝟑 𝟔/𝟏𝟎𝟎=(3 × 100 + 6)/100=𝟑𝟎𝟔/𝟏𝟎𝟎 𝟑 𝟔/𝟏𝟎 𝟔/𝟏𝟎𝟎=3+6/10+6/100=(3 × 100 + 6 × 10 + 6)/100=𝟑𝟔𝟔/𝟏𝟎𝟎 Since denominator is same, we compare numerators Therefore, Shortest length = 𝟑 𝟔/𝟏𝟎𝟎 Longest length = 𝟑 𝟔/𝟏𝟎 𝟔/𝟏𝟎𝟎 Question 1 – Page 55 (e) In each group, identify the longest and the shortest lengths. Mark each length on the scale. Converting them into same denominators 𝟖/𝟏𝟎 𝟐/𝟏𝟎𝟎=8/10+2/100=(8 × 10 + 2)/100=𝟖𝟐/𝟏𝟎𝟎 𝟗/𝟏𝟎𝟎 𝟏 𝟖/𝟏𝟎𝟎=(1 × 100 + 8)/100=𝟏𝟎𝟖/𝟏𝟎𝟎 Since denominator is same, we compare numerators Therefore, Shortest length = 𝟗/𝟏𝟎𝟎 Longest length = 1 𝟖/𝟏𝟎𝟎 Question 1 – Page 55 (f) In each group, identify the longest and the shortest lengths. Mark each length on the scale. Converting them into same denominators 𝟕 𝟑/𝟏𝟎 𝟓/𝟏𝟎𝟎=7+3/10+5/100=(7 × 100 + 3 × 10 + 5)/100=𝟕𝟑𝟓/𝟏𝟎𝟎 𝟕 𝟓/𝟏𝟎=75/10=75/10 ×10/10=𝟕𝟓𝟎/𝟏𝟎𝟎 𝟕 𝟒𝟏/𝟏𝟎𝟎=(𝟕 × 𝟏𝟎𝟎 + 𝟒𝟏)/𝟏𝟎𝟎=𝟕𝟒𝟏/𝟏𝟎𝟎 Since denominator is same, we compare numerators Therefore, Shortest length = 𝟕 𝟑/𝟏𝟎 𝟓/𝟏𝟎𝟎 Longest length = 𝟕 𝟓/𝟏𝟎 Question 1 – Page 55 (g) In each group, identify the longest and the shortest lengths. Mark each length on the scale. Converting them into same denominators 𝟔𝟓/𝟏𝟎 𝟏𝟓/𝟏𝟎𝟎=65/10+15/100=(65 × 10 + 15)/100=(650 + 15)/100 =𝟔𝟔𝟓/𝟏𝟎𝟎 𝟓 𝟖𝟕/𝟏𝟎𝟎=(5 × 100 + 87)/100=𝟓𝟖𝟕/𝟏𝟎𝟎 𝟓 𝟕/𝟏𝟎𝟎=(5 × 100 + 7)/100=𝟓𝟎𝟕/𝟏𝟎𝟎 Since denominator is same, we compare numerators Therefore, Shortest length = 𝟓 𝟕/𝟏𝟎𝟎 Longest length = 𝟔𝟓/𝟏𝟎 𝟏𝟓/𝟏𝟎𝟎