Question 3 - Finding General Solutions - Chapter 3 Class 11 Trigonometric Functions

Last updated at August 5, 2026 by

Example 20 - Find solution of sin x = - root 3/2 - Class 11 - Examples

Example 20 - Chapter 3 Class 11 Trigonometric Functions - Part 2

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Question 3 Find the solution of sin x = – √3/2 Let sin x = sin y also sin x = (−√3)/2 From (1) and (2) sin y = (−√3)/2 sin y = sin 4/3 π ⇒ y = 4/3 π Step 2 Since sin x = sin y General Solution is x = n π + (–1)n y where n ∈ Z Putting y = 4𝜋/3 x = n π + (–1)n 4/3 π where n ∈ Z

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