# Example 7

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Example 7 In what ratio does the point (– 4, 6) divide the line segment joining the points A(– 6, 10) and B(3, – 8)? Given points A(−6, 10) & B(3, −8) Let point C(−4, 6) We need to find ratio between AC & CB Let the ratio be k : 1 Hence, m1 = k , m2 = 1 Also, x1 = −6 , y1 = 10 x2 = 3 , y2 = −8 & x = −4 , y = 6 Using section formula x = (𝑚1 𝑥2 +𝑚2 𝑥1)/(𝑚1 + 𝑚2) −4 = (𝑘 ×3 +1 ×−6)/(𝑘 +1) −4 = (3𝑘 −6)/(𝑘 +1) −4(k + 1)= 3k − 6 −4k – 4 = 3k – 6 −4k – 3k = −6 + 4 −7k = −2 k = (−2)/(−7) k = 2/7 Hence, the ratio is k : 1 = 2/7 : 1 Multiplying 7 both sides = 7 × 2/7 : 7 × 1 = 2 : 7 So, the ratio is 2: 7

Chapter 7 Class 10 Coordinate Geometry

Concept wise

- Distance Formula
- Equidistant points
- Checking points collinear or not
- Type of triangle formed
- Type of quadrilateral formed
- Section Formula- Finding coordinates
- Section Formula- Finding coordinates of a point in a quadrilateral
- Finding ratio
- Area of triangle
- Given area, finding k
- Area of quadrilateral

About the Author

CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .