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Example 6 - Chapter 7 Class 10 Coordinate Geometry
Last updated at July 30, 2026 by Teachoo
Chapter 7 Class 10 Coordinate Geometry
Concept wise
- Distance Formula
- Equidistant points
- Checking points collinear or not
- Type of triangle formed
- Type of quadrilateral formed
-
Section Formula- Finding coordinates
- Section Formula- Finding coordinates of a point in a quadrilateral
- Finding ratio
- Area of triangle
- Given area, finding k
- Area of quadrilateral
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Transcript
Example 6 Find the coordinates of the point which divides the line segment joining the points (4, ā 3) and (8, 5) in the ratio 3 : 1 internally. Let the given points be A(4, ā3) & B(8, 5) Let the point be P(x, y) which divides AB in ratio 3 : 1 Finding x x = (š1 š„2 + š2 š„1)/(š1 + š2) Where, m1 = 3, m2 = 1 x1 = 4, x2 = 8 Putting values x = (3 Ć 8 + 1 Ć4)/(3 + 1) x = (24 + 4)/4 x = 28/4 x = 7 Finding y y = (š1 š¦2 + š2 š¦1)/(š1 + š2) Where, m1 = 3, m2 = 1 y1 = ā3, y2 = 5 Putting values y = (3 Ć 5 + 1 Ćā3)/(3 +1 ) y = (15 ā 3 )/4 y = (12 )/4 y = 3 Hence x = 7, y = 3 So, the required point is P(x, y) = P(7, 3)
