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Ex 7.1 , 1 Find the distance between the following pairs of points : (i) (2, 3), (4, 1) Let the two points be P(2, 3) & Q(4, 1) We need to find distance PQ PQ = √((π‘₯2 βˆ’π‘₯1)2+(𝑦2 βˆ’π‘¦1)2) Here, x1 = x coordinate of P = 2 y1 = y coordinate of P = 3 x2 = x coordinate of Q = 4 y2 = y coordinate of Q = 1 Putting values PQ = √((4 βˆ’2 )2+(1 βˆ’3)2) = √((2 )2+(βˆ’2)2) = √((2 Γ—2)+(βˆ’2 Γ—βˆ’2) ) = √(4+4) = √8 = √(4(2)) = √(4 Γ—(2)) = √4 Γ— √2 = 2 Γ— √2 = 2√𝟐

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.