Ex 7.2, 5 - Find ratio in which A(1, -5) and B(-4, 5) - Finding ratio

  1. Chapter 7 Class 10 Coordinate Geometry
  2. Serial order wise
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Ex 7.2 , 5 Find the ratio in which the line segment joining A(1, – 5) and B(– 4, 5) is divided by the x−axis. Also find the coordinates of the point of division. Now, we have to find ratio Let ratio be k : 1 Hence, m1 = k , m2 = 1 x1 = 1 , y1 = −5 x2 = −4 , y2 = 5 Also, x = x , y = 0 Using section formula y = (𝑚_1 𝑦_2+𝑚_2 𝑦_1)/(𝑚_1+𝑚_2 ) 0 = (𝑘 ×5 +1 ×−5)/(𝑘 +1) 0 = (5𝑘 −5)/(𝑘 +1) 0(k + 1)= 5k – 5 0 = 5k – 5 5k – 5 = 0 5k = 5 k = 5/5 k = 1 Hence, k = 1 Now, we need to find x also x = (𝑚1 𝑥2 +𝑚2 𝑥1)/(𝑚1 + 𝑚2) = (𝑘 ×−4 +1 ×1)/(𝑘 +1) = (1 ×−4 +1 ×1)/(1 +1) = (−4 +1)/2 = (−3)/2 Hence the coordinate of point is P(x, 0) = P((−3)/2, 0)

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