Last updated at May 29, 2018 by Teachoo

Transcript

Example 18 Solve the following pair of equations by reducing them to a pair of linear equations : 5/( 1) + 1/( 2) = 2 6/( 1) 3/( 2) = 1 5/( 1) + 1/( 2) = 2 6/( 1) 3/( 2) = 1 Thus, our equations are 5u + v = 2 (3) 6u 3v = 1 (4) From (3) 5u + v = 2 v = 2 5u Putting value of v in (4) 6u 3v = 1 6u 3(2 5u) = 1 6u 6 + 15u = 1 6u + 15u = 1 + 6 21u = 7 u = 7/21 u = 1/3 Putting u = 1/3 in equation (3) 5u + v = 2 5(1/3) + v = 2 5/3 + v = 2 v = 2 5/3 v = (2(3) 5)/3 v = (6 5)/3 v = 1/3 Hence, u = 1/3 & v = 1/3 But we need to find x & y So, x = 4, y = 5 is the solution of our equations

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.