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Ex  15.1, 12 - The frequency distribution table represents - Grouped frequency

  1. Class 9
  2. Important Questions for Exam - Class 9
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Ex 15.1, 12 The above frequency distribution table represents the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12 − 0.16 on any of these days. Total number of days = 30 Number days for which the concentration of sulphur dioxide was in the interval of 0.12 − 0.16 = 2 P(concentration of sulphur dioxide as in interval 0.12 – 0.16) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑑𝑎𝑦𝑠 𝑤ℎ𝑒𝑛 𝑐𝑜𝑛𝑐𝑒𝑛𝑡𝑟𝑎𝑡𝑖𝑜𝑛 𝑖𝑠 𝑖𝑛 𝑖𝑛𝑡𝑒𝑟𝑣𝑎𝑙 0.12 − 0.16)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑑𝑎𝑦𝑠) = 2/30 = 1/15

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