Example  2 - Chapter 13 Class 11 Limits and Derivatives - Part 6

Example  2 - Chapter 13 Class 11 Limits and Derivatives - Part 7

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Transcript

Example 2 Find the limits: (iv) lim┬(xβ†’2) [(x3 βˆ’2π‘₯2)/(x2βˆ’5x+6)] lim┬(xβ†’2) [(x3 βˆ’ 2π‘₯2)/(x2 βˆ’ 5x + 6)] = lim┬(xβ†’2) ((x2 (x βˆ’ 2))/(π‘₯2 βˆ’ 3π‘₯ βˆ’ 2π‘₯ + 6)) = lim┬(xβ†’2) ((x2 (x βˆ’ 2))/(x (x βˆ’ 3) βˆ’ 2 (x βˆ’ 3) )) = lim┬(xβ†’2) ((x2 (x βˆ’ 2))/((x βˆ’ 2) (x βˆ’ 3) )) = (π₯𝐒𝐦)┬(π±β†’πŸ) ((𝐱𝟐 )/((𝐱 βˆ’ πŸ‘) )) Putting x = 2 = (2)2/(2 βˆ’ 3) = (2)2/(2 βˆ’ 3) = 4/(βˆ’1) = – 4

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