Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Chapter 13 Class 9 Surface Areas and Volumes
Question 6 Important Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 4 Important Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Example 3 Important
Ex 11.1, 3 Important You are here
Ex 11.1, 5 Important
Ex 11.2, 3 Important
Ex 11.2, 8 Important
Ex 11.2, 9 Important
Question 6 Important Deleted for CBSE Board 2024 Exams
Question 8 Important Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Ex 11.3, 5 Important
Ex 11.3, 6 Important
Ex 11.3, 7 Important
Ex 11.3, 8 Important
Example 11 Important
Ex 11.4, 4 Important
Surface Area and Volume Formulas Important
Chapter 13 Class 9 Surface Areas and Volumes
Last updated at May 29, 2023 by Teachoo
Ex 11.1, 3 Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Find radius of the base and [ =22/7] It is given that Curved Surface Area of cone =308 rl = 308 22/7 14= 308 22 2= 308 r = (308/(2 22)) cm r = 7 cm Therefore, the radius of the circular end of the cone is 7 cm. Ex 11.1, 3 Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Find (ii) total surface area of the cone. [ =22/7] We know that l = 14 cm, r = 7 cm Total surface area of cone = r(l + r) = 22/7 7 (14 + 7) = 22/7 7 21 = 22 1 21 = 462 cm2 Therefore, the total surface area of the cone is 462 cm2.