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Chapter 13 Class 9 Surface Areas and Volumes
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Question 9 Important Deleted for CBSE Board 2024 Exams
Example 3 Important
Ex 11.1, 3 Important
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Question 6 Important Deleted for CBSE Board 2024 Exams
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Question 9 Important Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Ex 11.3, 5 Important
Ex 11.3, 6 Important
Ex 11.3, 7 Important
Ex 11.3, 8 Important
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Surface Area and Volume Formulas Important
Chapter 13 Class 9 Surface Areas and Volumes
Last updated at May 29, 2023 by Teachoo
Question 4 The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in m2? [π΄π π π’ππ π= 22/7] Roller is of form cylinder Radius = π·πππππ‘ππ/2 = 84/2 = 42 cm Area of roller = Curved surface of cylinder = 2Οrh = (2Γ22/7Γ42Γ120) cm2 = 31680 cm2 Area of 1 revolution = Area of roller = 31680 cm2 Area of 500 revolution = 500 Γ 31680 cm2 Area of playground = 15840000 cm2 = 15840000 Γ1/(100 ) Γ1/(100 )m2 = 1584 m2