Ex 1.1, 2 (ii) - Chapter 1 Class 10 Real Numbers

Last updated at August 17, 2026 by

Ex 1.1, 2 (ii) - Find HCF and LCM of 510 and 92 (and verify product) - Ex 1.1

part 2 - Ex 1.1, 2 (ii) - Ex 1.1 - Serial order wise - Chapter 1 Class 10 Real Numbers
part 3 - Ex 1.1, 2 (ii) - Ex 1.1 - Serial order wise - Chapter 1 Class 10 Real Numbers

 

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Ex 1.1, 2 Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (ii) 510 and 92 Finding HCF ∴ H.C.F = 2 510 = 2 × 3 × 5 × 17 92 = 2 × 2 × 23 Finding L.C.M L.C.M = 2 × 2 × 3 × 5 × 17 × 23 = 23460 Now, we have to verify that H.C.F × L.C.M = Product of 2 numbers H.C.F × L.C.M = 2 × 23460 = 46920 Product of two numbers = 510 × 92 = 46920 Since L.H.S = R.H.S Hence verified

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