Ex 1.1, 2 (ii) - Chapter 1 Class 10 Real Numbers

Last updated at Dec. 16, 2024 by

Ex 1.1, 2 (ii) - Find HCF and LCM of 510 and 92 (and verify product) - Ex 1.1

part 2 - Ex 1.1, 2 (ii) - Ex 1.1 - Serial order wise - Chapter 1 Class 10 Real Numbers
part 3 - Ex 1.1, 2 (ii) - Ex 1.1 - Serial order wise - Chapter 1 Class 10 Real Numbers

 

Remove Ads

Transcript

Ex 1.1, 2 Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (ii) 510 and 92 Finding HCF ∴ H.C.F = 2 510 = 2 × 3 × 5 × 17 92 = 2 × 2 × 23 Finding L.C.M L.C.M = 2 × 2 × 3 × 5 × 17 × 23 = 23460 Now, we have to verify that H.C.F × L.C.M = Product of 2 numbers H.C.F × L.C.M = 2 × 23460 = 46920 Product of two numbers = 510 × 92 = 46920 Since L.H.S = R.H.S Hence verified

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo