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Example 5 - Chapter 1 Class 10 Real Numbers (Term 1)

Last updated at May 29, 2018 by

Example 5 - Consider numbers 4n, where n is a natural - Prime Factorization

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Example 5 Consider the numbers 4n , where n is a natural number. Check whether there is any value of n for which 4n ends with the digit zero. Let us take the example of a number which ends with the digit 0 So, 10 = 2 × 5 100 = 2 × 2 × 5 × 5 Here we note that numbers ending with 0 has both 2 and 5 as their prime factors Whereas 4n = (2 × 2) n Does not have 5 as a prime factor. So, it does not end with zero. Therefore, 4n cannot end with zero for any natural number n

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