1. Chapter 1 Class 10 Real Numbers
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Example 6

Last updated at Dec. 8, 2016 by

Example 6 - Find LCM HCF of 6 and 20 by prime factorisation - Examples

  1. Chapter 1 Class 10 Real Numbers
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Example 6 (Method 1) Find the LCM and HCF of 6 and 20 by the prime factorisation method. 6 = 2 × 3 6 = 21 × 31 H.C.F = Product of smallest power of each common prime factor = 21 = 2 L.C.M = Product of greatest power of each prime factor = 22 × 31 × 5 = 4 × 3 × 5 = 60 Example 6 (Method 2) Find the LCM and HCF of 6 and 20 by the prime factorisation method. 6 = 2 × 3 20 = 2 × 2 × 5 H.C.F = 2 Finding L.C.M L.C.M = 2 × 2 × 3 × 5 = 60

Chapter 1 Class 10 Real Numbers
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