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Example 6 - Chapter 1 Class 10 Real Numbers (Term 1)

Last updated at May 29, 2018 by

Example 6 - Find LCM HCF of 6 and 20 by prime factorisation - LCM/HCF

Example 6 - Chapter 1 Class 10 Real Numbers - Part 2
Example 6 - Chapter 1 Class 10 Real Numbers - Part 3

Transcript

Example 6 (Method 1) Find the LCM and HCF of 6 and 20 by the prime factorisation method. 6 = 2 3 6 = 21 31 H.C.F = Product of smallest power of each common prime factor = 21 = 2 L.C.M = Product of greatest power of each prime factor = 22 31 5 = 4 3 5 = 60 Example 6 (Method 2) Find the LCM and HCF of 6 and 20 by the prime factorisation method. 6 = 2 3 20 = 2 2 5 H.C.F = 2 Finding L.C.M L.C.M = 2 2 3 5 = 60

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