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Example 7 - Find HCF of 96 and 404 by prime factorisation - LCM/HCF

Example 7 - Chapter 1 Class 10 Real Numbers - Part 2

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Example 7 - Chapter 1 Class 10 Real Numbers - Part 3
Example 7 - Chapter 1 Class 10 Real Numbers - Part 4

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Transcript

Example 7 (Method 1) Find the HCF of 96 and 404 by the prime factorisation method. Hence, find their LCM 96 = 2 2 2 2 2 3 = 25 31 H.C.F = Product of smallest power of each common prime factor = 22 = 4 We know that H.C.F L.C.M = Product of numbers 4 L.C.M = 96 404 L.C.M = (96 404)/4 L.C.M = 9696 Example 7 (Method 2) Find the HCF of 96 and 404 by the prime factorisation method. Hence, find their LCM 96 = 2 2 2 2 2 3 404 = 2 2 101 H.C.F = 2 2 = 4 We know that H.C.F L.C.M = Product of numbers 4 L.C.M = 96 404 L.C.M = (96 404)/4 L.C.M = 9696

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.