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Example 7 - Find HCF of 96 and 404 by prime factorisation - LCM/HCF

  1. Chapter 1 Class 10 Real Numbers
  2. Serial order wise
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Example 7 (Method 1) Find the HCF of 96 and 404 by the prime factorisation method. Hence, find their LCM 96 = 2 × 2 × 2 × 2 × 2 × 3 = 25 × 31 H.C.F = Product of smallest power of each common prime factor = 22 = 4 We know that H.C.F × L.C.M = Product of numbers 4 × L.C.M = 96 × 404 L.C.M = (96 × 404)/4 L.C.M = 9696 Example 7 (Method 2) Find the HCF of 96 and 404 by the prime factorisation method. Hence, find their LCM 96 = 2 × 2 × 2 × 2 × 2 × 3 404 = 2 × 2 × 101 H.C.F = 2 × 2 = 4 We know that H.C.F × L.C.M = Product of numbers 4 × L.C.M = 96 × 404 L.C.M = (96 × 404)/4 L.C.M = 9696

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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