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Example 3 - Chapter 1 Class 10 Real Numbers

Last updated at May 29, 2023 by

Example 7 - Find HCF of 96 and 404 by prime factorisation - LCM/HCF

Example 7 - Chapter 1 Class 10 Real Numbers - Part 2

Example 7 - Chapter 1 Class 10 Real Numbers - Part 3 Example 7 - Chapter 1 Class 10 Real Numbers - Part 4

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Example 3 (Method 1) Find the HCF of 96 and 404 by the prime factorisation method. Hence, find their LCM 96 = 2 2 2 2 2 3 = 25 31 H.C.F = Product of smallest power of each common prime factor = 22 = 4 We know that H.C.F L.C.M = Product of numbers 4 L.C.M = 96 404 L.C.M = (96 404)/4 L.C.M = 9696 Example 3 (Method 2) Find the HCF of 96 and 404 by the prime factorisation method. Hence, find their LCM 96 = 2 2 2 2 2 3 404 = 2 2 101 H.C.F = 2 2 = 4 We know that H.C.F L.C.M = Product of numbers 4 L.C.M = 96 404 L.C.M = (96 404)/4 L.C.M = 9696

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.