Check sibling questions

Ex 1.2, 2 - Find LCM and HCF of the following pairs (i) 26 & 91 (ii)

Ex 1.2, 2 - Chapter 1 Class 10 Real Numbers - Part 2

This video is only available for Teachoo black users

Ex 1.2, 2 - Chapter 1 Class 10 Real Numbers - Part 3 Ex 1.2, 2 - Chapter 1 Class 10 Real Numbers - Part 4 Ex 1.2, 2 - Chapter 1 Class 10 Real Numbers - Part 5

This video is only available for Teachoo black users

 


Transcript

Ex 1.2 , 2 (Method 1) Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. 26 and 91 H.C.F = Product of smallest power of each common prime factor = 13 L.C.M = Product of greatest power of each prime factor = 2 × 13 × 7 = 182 Now, we have to verify that H.C.F × L.C.M = Product of 2 numbers H.C.F × L.C.M = 13 × 182 = 2386 Product of two numbers = 26 × 91 = 2386 Since L.H.S = R.H.S Hence verified Ex 1.2 , 2 (Method 2) Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. 26 and 91 26 = 2 × 13 91 = 7 × 13 H.C.F = 13 Finding L.C.M L.C.M = 2 × 13 × 7 = 182 Now, we have to verify that H.C.F × L.C.M = Product of 2 numbers H.C.F × L.C.M = 13 × 182 = 2386 Product of two numbers = 26 × 91 = 2386 Since L.H.S = R.H.S Hence verified

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.