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Ex 1.1, 2 (i) - Chapter 1 Class 10 Real Numbers
Last updated at May 29, 2023 by Teachoo
Transcript
Ex 1.1 , 2 (Method 1) Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. 26 and 91 H.C.F = Product of smallest power of each common prime factor = 13 L.C.M = Product of greatest power of each prime factor = 2 × 13 × 7 = 182 Now, we have to verify that H.C.F × L.C.M = Product of 2 numbers H.C.F × L.C.M = 13 × 182 = 2386 Product of two numbers = 26 × 91 = 2386 Since L.H.S = R.H.S Hence verified Ex 1.1 , 2 (Method 2) Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. 26 and 91 26 = 2 × 13 91 = 7 × 13 H.C.F = 13 Finding L.C.M L.C.M = 2 × 13 × 7 = 182 Now, we have to verify that H.C.F × L.C.M = Product of 2 numbers H.C.F × L.C.M = 13 × 182 = 2386 Product of two numbers = 26 × 91 = 2386 Since L.H.S = R.H.S Hence verified
