1. Chapter 1 Class 10 Real Numbers (Term 1)
  2. Serial order wise
  3. Ex 1.2

Ex 1.2, 4 - Chapter 1 Class 10 Real Numbers (Term 1)

Last updated at May 29, 2018 by

Ex 1.2, 4 - Given that HCF (306, 657) = 9, find LCM - LCM/HCF

  1. Chapter 1 Class 10 Real Numbers (Term 1)
  2. Serial order wise

    3. Ex 1.2

    Ex 1.3 →

Transcript

Ex 1.2 , 4 Given that HCF (306, 657) = 9, find LCM (306, 657). We know that H.C.F × L.C.M = Product of numbers 9 × L.C.M = 306 × 657 L.C.M = (306 × 657)/9 L.C.M = 22338 Hence L.C.M of 306 & 657 is 22338

Chapter 1 Class 10 Real Numbers (Term 1)
Serial order wise

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