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Ex 1.2, 3 - Chapter 1 Class 10 Real Numbers - Part 7

Ex 1.2, 3 - Chapter 1 Class 10 Real Numbers - Part 8
Ex 1.2, 3 - Chapter 1 Class 10 Real Numbers - Part 9

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Ex 1.2 , 3 (Method 1) Find the LCM and HCF of the following integers by applying the prime factorisation method. (iii) 8, 9 and 25 8 = 2 × 2 × 2 = 23 9 = 3 × 3 = 32 25 = 5 × 5 = 52 H.C.F = Product of smallest power of each common prime factor = 1 L.C.M = Product of greatest power of each prime factor = 23 × 32 × 52 = 8 × 9 × 25 = 1800 Ex 1.2 , 3 (Method 2) Find the LCM and HCF of the following integers by applying the prime factorisation method. (iii) 8, 9 and 25 8 = 2 × 2 × 2 9 = 3 × 3 25 = 5 × 5 H.C.F = 1 L.C.M = 2 × 2 × 2 × 3 × 3 × 5 × 5 = 8 × 9 × 25 = 1800

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.