Ex 1.1, 3 (iii) - Chapter 1 Class 10 Real Numbers

Last updated at December 16, 2024 by

Find LCM and HCF of 8, 9 and 25 [with Video] - Teachoo - Ex 1.1 - Ex 1.1 part 2 - Ex 1.1, 3 (iii) - Ex 1.1 - Serial order wise - Chapter 1 Class 10 Real Numbers

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Ex 1.1, 3 Find the LCM and HCF of the following integers by applying the prime factorisation method. (iii) 8, 9 and 25 Finding HCF Since no factor is common So, 1 must be common ∴ H.C.F = 1 8 = 2 × 2 × 2 9 = 3 × 3 25 = 5 × 5 Finding L.C.M L.C.M = 2 × 2 × 2 × 3 × 3 × 5 × 5 = 8 × 9 × 25 = 1800

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo