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Important Linear Equation Questions
Last updated at August 12, 2026 by Teachoo
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Transcript
Question 7 Solve the following pair of linear equations: (iii) ๐ฅ/๐ โ ๐ฆ/๐ = 0 ax + by = a2 + b2 ๐ฅ/๐ โ ๐ฆ/๐ = 0 โฆ(1) ax + by = ๐2+๐2 โฆ(2) Solving Equation (1) ๐ฅ/๐ โ ๐ฆ/๐ = 0 (๐๐ฅ โ ๐๐ฆ)/๐๐ = 0 bx โ ay = 0 Now, solving equations (2) & (3) bx โ ay = 0 Multiplying both sides by b b(bx โ ay) = b ร 0 b2x โ aby = 0 ax + by = a2 + b2 Multiplying both sides by a a(ax + by) = a(a2 + b2) a2x + aby = a3 + ab2 Hence, our equations are b2x โ aby = 0 โฆ(4) a2x + aby = a3 + ab2 โฆ(5) From equation (4) b2x โ aby = 0 b2x = aby aby = b2x y = (๐^2 ๐ฅ)/๐๐ y = ๐๐ฅ/๐ Putting y = ๐๐ฅ/๐ in equation (5) a2x + aby = a3 + ab2 a2๐ฅ + ab(๐๐ฅ/๐) = a3 + ab2 a2๐ฅ + b2๐ฅ = a3 + ab2 (a2 + b2) ๐ฅ = a (a2 + b2) ๐ฅ = (๐(๐^2 + ๐^2))/((๐^2 + ๐^2)) ๐ = a Putting ๐ฅ = a in equation (4) b2๐ฅ โ aby = 0 b2(a) โ aby = 0 ab2 โ aby = 0 ab2 = aby aby = ab2 y = (๐๐^2)/๐๐ y = b Therefore, ๐ = a and y = b