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Ex 10.4, 5 - Three girls Reshma, Salma and Mandip are - Ex 10.4

Ex 10.4, 5 - Chapter 10 Class 9 Circles - Part 2
Ex 10.4, 5 - Chapter 10 Class 9 Circles - Part 3
Ex 10.4, 5 - Chapter 10 Class 9 Circles - Part 4
Ex 10.4, 5 - Chapter 10 Class 9 Circles - Part 5

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Transcript

Ex 10.4, 5 Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip? Given: Let Reshma , Salma and Mandip be donated by points R,S & M resp. Given radius = 5 m & RS = 6m, SM =6m To find: Length of RM Construction: Join OR, OS, OM Let RM intersect OS at X Solution: In ORS & OMS OR = OM OS = OS RS = SM ORS OMS ROS = MOS In ORX & OMX OR = OM ROX = MOX OX = OX ORX OMX RX = MX Since RX = MX So, OX bisects chord RM, OX RM Now, Let OX = x, So, XS = OS OX = 5 x From (3) & (4) 25 x2 = 11 x2 + 10x 25 11 x2 + x2 = 10x 14 = 10x 10x = 14 x = 14/10 x = 1.4 Putting value of x in (3) RX2 = 25 x2 RX2 = 25 (1.4)2 RX2 = 25 1.96 RX2 = 23.04 RX = ("23.04" ) RX = 4.8 Therefore, RM = 2RX = 2 4.8 = 9.6 m Distance between Reshma and Mandip is 9.6 m

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.