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Case Study Based- 4

100m RACE

A stopwatch was used to find the time that it took a group of students to run 100 m.

Note: Check more Case Based Questions for - Statistics Class 10 (Chapter 14 Class 10)

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100m RACE A stopwatch was used to find the time that it took a group

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Question 20 - CBSE Class 10 Sample Paper for 2021 Boards - Maths Standard - Part 2

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Question 20 - CBSE Class 10 Sample Paper for 2021 Boards - Maths Standard - Part 4

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Note: Check more Case Based Questions for - Statistics Class 10 (Chapter 14 Class 10)

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Question 20 Case Study Based- 4 100m RACE A stopwatch was used to find the time that it took a group of students to run 100 m. (a) Estimate the mean time taken by a student to finish the race. (i) 54 (ii) 63 (iii) 43 (iv) 50 Mean(π‘₯ Μ…) = (βˆ‘β–’π’‡π’Šπ’™π’Š)/(βˆ‘β–’π’‡π’Š) = 1720/40 = 43 Mean time is 43 (b) What wiil be the upper limit of the modal class ? (i) 20 (ii) 40 (iii) 60 (iv) 80 Modal class is class with highest frequency ∴ 40 βˆ’ 60 is the modal class And Upper limit = 60 (c) The construction of cummulative frequency table is useful in determining the (i) Mean (ii) Median (iii) Mode (iv) All of the aboveCummulative frequency table is used to find the Median (d) The sum of lower limits of median class and modal class is (i) 60 (ii) 100 (iii) 80 (iv) 140 Modal class is class with highest frequency ∴ 40 βˆ’ 60 is modal class To find Median Class, We find cummulative freqeuncy 𝑛/2=40/2 = 20 ∴ 40 βˆ’ 60 has cummulative frequency greater than 20 Thus, 40 βˆ’ 60 is the Median Class ∴ Sum of Lower Limits of Median class and Modal class = 40 + 40 = 80 (e) How many students finished the race within 1 minute? (i) 18 (ii) 37 (iii) 31 (iv) 8 Students finished the race within 1 minute = Students between 0 βˆ’ 20 + Students between 20 βˆ’ 40 + Students between 40 βˆ’ 60 = 8 + 10 + 13 = 31

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