In the figure, quadrilateral ABCD is circumscribing a circle with centre O and AD⊥AB. If radius of incircle is 10cm, then the value of x is

In figure, quadrilateral ABCD is circumscribing a circle with centre O

Question 26 - CBSE Class 10 Sample Paper for 2021 Boards - Maths Standard - Part 2
Question 26 - CBSE Class 10 Sample Paper for 2021 Boards - Maths Standard - Part 3

Go Ad-free

Transcript

Question 26 In the figure, quadrilateral ABCD is circumscribing a circle with centre O and AD⊥ AB. If radius of incircle is 10 cm, then the value of x is Since Tangent is perpendicular to Radius OS ⊥ AD and OP ⊥ AB Thus, ∠ OSA = 90° and ∠ OPA = 90° And, ∠ SOP = 90° Also, AS = AP (Tangents drawn from external point are equal) Thus, In OPAS, All angles are 90° and Adjacent sides are equal ∴ OPAS is a square So, AP = OS = 10 cm Also, Tangent drawn from external point are equal ∴ CQ = CR = 27 cm And, BP = BQ Given CB = 38 cm CQ + BQ = 38 CQ + BP = 38 27 + BP = 38 BP = 38 − 27 BP = 11 cm Thus, x = AB = AP + BP = 10 + 11 = 21 cm

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.