PQ is a tangent to a circle with centre O at point P. If ∆OPQ is an isosceles triangle, then find ∠OQP

PQ is a tangent to a circle with centre O at point P. If OPQ is an

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Question 9 (Choice - 2) PQ is a tangent to a circle with centre O at point P. If ∆OPQ is an isosceles triangle, then find ∠OQPPQ is the tangent and OQ is the radius We know that Tangent is perpendicular to radius ∴ ∠ OPQ = 90° Since Δ OPQ is isosceles OP = PQ ∴ ∠ OQP = ∠ POQ Thus, ∠ OQP = 1/2 × 90° = 45° (Isosceles triangle Property)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.