If √3  sin⁡θ-cos⁡θ = 0 and 0˚ < θ < 90°, find the value of θ

If √3 sin θ - cos θ = 0 and 0 < θ < 90, find the value of θ [Video]

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Question 25 (Choice - 2) If √3 sin⁡𝜃−cos⁡𝜃 = 0 and 0˚ < 𝜃 < 90°, find the value of 𝜃Given √3 sin⁡𝜃−cos⁡𝜃 = 0 √3 sin⁡𝜃=cos⁡𝜃 sin⁡𝜃/cos⁡𝜃 =1/√3 𝑡𝑎𝑛 θ=1/√3 𝑡𝑎𝑛 θ=tan⁡〖30° 〗 ∴ θ = 30°

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