The COVID-19 pandemic, also known as coronavirus pandemic, is an ongoing pandemic of coronavirus disease caused by the transmission of severe acute respiratory syndrome coronavirus 2 (SARS-CoV-2) among humans. The following tables shows the age distribution of case admitted during a day in two different hospitals

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Refer to Table 1

Question 1

The average age for which maximum cases occurred is
(a) 32.24
(b) 34.36
(c) 36.82
(d) 42.24

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Question 2

The upper limit of modal class is
(a) 15
(b) 25
(c) 35
(d) 45

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Question 3

The mean of the given data is
(a) 26.2
(b) 32.4
(c) 33.5
(d) 35.4

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Refer to table 2

Question 4

The mode of the given data is
(a) 41.4
(b) 48.2
(c) 55.3
(d) 64.6

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Question 5

The median of the given data is
(a) 32.7
(b) 40.2
(c) 42.3
(d) 48.6

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  1. Chapter 14 Class 10 Statistics (Term 2)
  2. Serial order wise

Transcript

Question The COVID-19 pandemic, also known as coronavirus pandemic, is an ongoing pandemic of coronavirus disease caused by the transmission of severe acute respiratory syndrome coronavirus 2 (SARS-CoV-2) among humans. The following tables shows the age distribution of case admitted during a day in two different hospitalsRefer to Table 1 Question 1 The average age for which maximum cases occurred is (a) 32.24 (b) 34.36 (c) 36.82 (d) 42.24(c) 36.82 Now, When we want to find average age, we find mean But, when we need to find average age of maximum cases, we need to find mode Finding Mode Mode = l + (๐’‡๐Ÿ โˆ’ ๐’‡๐ŸŽ)/(๐Ÿ๐’‡๐Ÿ โˆ’ ๐’‡๐ŸŽ โˆ’ ๐’‡๐Ÿ) ร— h Modal class = Interval with highest frequency = 35 โ€“ 45 where l = lower limit of modal class h = class-interval f1 = frequency of the modal class f0 = frequency of class before modal class f2 = frequency of class after modal class Putting values in formula Mode = l + (๐‘“1 โˆ’๐‘“0)/(2๐‘“1 โˆ’๐‘“0 โˆ’๐‘“2) ร— h = 35 + (๐Ÿ๐Ÿ‘ โˆ’๐Ÿ๐Ÿ)/(๐Ÿ(๐Ÿ๐Ÿ‘) โˆ’ ๐Ÿ๐Ÿ โˆ’ ๐Ÿ๐Ÿ’) ร— 10 = 35 + 2/(46 โˆ’ 35) ร— 10 = 35 + 2/11 ร— 10 = 35 + 1.818 = 36.818 โ‰ˆ 36.82 So, the correct answer is (c) Question 2 The upper limit of modal class is (a) 15 (b) 25 (c) 35 (d) 45(d) 45 Modal class is class with highest frequency Since 35 โˆ’ 45 has highest frequency 23 โˆด It is the modal class And Upper limit of Modal Class = 45 So, the correct answer is (d) Question 3 The mean of the given data is (a) 26.2 (b) 32.4 (c) 33.5 (d) 35.4(d) 35.4 Mean(๐‘ฅ ฬ…) = (โˆ‘โ–’๐’‡๐’Š๐’™๐’Š)/(โˆ‘โ–’๐’‡๐’Š) = 2830/80 = 35.375 = 35.4 So, the correct answer is (d) Refer to table 2 Question 4 The mode of the given data is (a) 41.4 (b) 48.2 (c) 55.3 (d) 64.6(a) 41.4 Mode = l + (๐’‡๐Ÿ โˆ’ ๐’‡๐ŸŽ)/(๐Ÿ๐’‡๐Ÿ โˆ’ ๐’‡๐ŸŽ โˆ’ ๐’‡๐Ÿ) ร— h Modal class = Interval with highest frequency = 35 โ€“ 45 where l = lower limit of modal class h = class-interval f1 = frequency of the modal class f0 = frequency of class before modal class f2 = frequency of class after modal class Putting values in formula Mode = l + (๐‘“1 โˆ’๐‘“0)/(2๐‘“1 โˆ’๐‘“0 โˆ’๐‘“2) ร— h = 35 + (๐Ÿ’๐Ÿ โˆ’ ๐Ÿ๐ŸŽ)/(๐Ÿ(๐Ÿ’๐Ÿ) โˆ’๐Ÿ๐ŸŽ โˆ’๐Ÿ๐Ÿ’) ร— 10 = 35 + 32/(84 โˆ’34) ร— 10 = 35 + 32/50 ร— 10 = 35 + 32/5 = 35 + 6.4 = 41.4 Question 5 The median of the given data is (a) 32.7 (b) 40.2 (c) 42.3 (d) 48.6(b) 40.2 Median = l + (๐‘ต/๐Ÿ โˆ’๐’„๐’‡)/๐’‡ ร— h Here, ๐‘ต/๐Ÿ โˆด 35 โ€“ 45 is the median class And, l = lower limit of median class h = class-interval cf = cumulative frequency of the class before median class f = frequency of the median class Putting values in formula Median = l + (๐‘/2 โˆ’๐‘๐‘“)/๐‘“ ร— h = 35 + (๐Ÿ“๐Ÿ” โˆ’๐Ÿ‘๐Ÿ’)/๐Ÿ’๐Ÿ ร— 10 = 35 + 22/42 ร— 10 = 35 + 110/21 = 35 + 5.23 = 40.23 So, the correct answer is (b)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.