Check sibling questions
Chapter 14 Class 10 Statistics
Serial order wise

Question

The maximum bowling speeds, in km per hour, of 33 players at a cricket coaching center are given as follows.

Speed (in Km/h)

85 − 100

100 − 115

115 − 130

130 − 145

No. of Players

11

9

8

5

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Question 1

What is the modal class of the given data? 

(a) 85-100  

(b) 100-115

(c) 115-130  

(d) 130-145

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Question 2

What is the value of class interval for the given data set? 

(a) 10  

(b) 15

(c) 5  

(d) 20

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Question 3

What is the median class of the given data? 

(a) 85-100   (b) 100-115

(c) 115-130   (d) 130-145

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Question 4

What is the median of bowling speed? 

(a) 109.17 km/hr (Approx)  

(b) 109.71 km/hr (Approx) 

(c) 107.17 km/hr (Approx)  

(d) 109.19 km/hr (Approx)

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Question 5

What is the sum of lower limit of modal class and upper limit of median class? 

(a) 100  

(b) 200

(c) 300  

(d) 400

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Transcript

Question The maximum bowling speeds, in km per hour, of 33 players at a cricket coaching center are given as follows. Question 1 What is the modal class of the given data? (a) 85-100 (b) 100-115 (c) 115-130 (d) 130-145 Modal class is class with highest frequency Since 85 – 100 has highest frequency 11 ∴ It is the modal class So, the correct answer is (a) Question 2 What is the value of class interval for the given data set? (a) 10 (b) 15 (c) 5 (d) 20 Class interval = Upper class limit – Lower class limit = 100 – 85 = 15 So, the correct answer is (b) Question 3 What is the median class of the given data? (a) 85-100 (b) 100-115 (c) 115-130 (d) 130-145 Here, 𝑵/𝟐=33/2= 16.5 ∴ 100 – 115 is the median class So, the correct answer is (a) Question 4 What is the median of bowling speed? (a) 109.17 km/hr (Approx) (b) 109.71 km/hr (Approx) (c) 107.17 km/hr (Approx) (d) 109.19 km/hr (Approx)Median = l + (𝑵/𝟐 −𝒄𝒇)/𝒇 × h ∴ 100 – 115 is the median class And, l = lower limit of median class = 100 h = class-interval = 15 cf = cumulative frequency of the class before median class = 11 f = frequency of the median class = 9 Putting values in formula Median = l + (𝑁/2 −𝑐𝑓)/𝑓 × h = 100 + (𝟏𝟔.𝟓 −𝟏𝟏)/𝟗 × 15 = 100 + 5.5/9 × 15 = 100 + 27.5/3 = 100 + 9.17 = 109.17 km/hr (approx.) So, the correct answer is (a) Question 5 What is the sum of lower limit of modal class and upper limit of median class? (a) 100 (b) 200 (c) 300 (d) 400 Modal Class is 85 – 100 Lower limit of Modal Class = 85 Median Class is 100 – 115 Upper limit of Median Class = 115 Sum of lower limit of modal class and upper limit of median class = 85 + 115 = 200 So, the correct answer is (B)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.